Moin Leute,

und wieder steh ich vor einem ungelöstem Problem ;-)

Wie generiert man unter Perl eine random-zahl? Unter C gabs früher (ganz ganz früer ;-) mal so ne funktion. Gibts da auch was für Perl.

Gruß

euer

Raudi

Hallo Raudi!

folgendes steht zu deinem Problem im Perl-Cookbook.

Ich hoffe du kannst Englisch.

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2.7. Generating Random Numbers

Problem

You want to make random numbers in a given range, inclusive, such as when you randomly pick an array index, simulate rolling a die in a game of chance, or generate a random password.

Solution

Use Perl's rand function.

$random = int( rand( $Y-$X+1 ) ) + $X;

Discussion

This code generates and prints a random integer between 25 and 75, inclusive:

$random = int( rand(51)) + 25;

print "$random\n";

The rand function returns a fractional number, from (and including) 0 up to (but not including) its argument. We give it an argument of 51 to get a number that can be 0 or more, but never 51 or more. We take the integer portion of this to get a number from 0 to 50, inclusive (50.99999.... will be turned to 50 by int). We then add 25 to it, to get a number from 25 to 75, inclusive.

A common application of this is the random selection of an element from an array:

$elt = $array[ rand @array ];

And generating a random password from a sequence of characters:

@chars = ( "A" .. "Z", "a" .. "z", 0 .. 9, qw(! @ $ % ^ & *) );

$password = join("", @chars[ map { rand @chars } ( 1 .. 8 ) ]);

We use map to generate eight random indices into @chars, extract the corresponding characters with a slice, and join them together to form the random password. This isn't a good random number, though, as its security relies on the choice of seed, which is based on the time the program started. See Recipe 2.8 for a way to better seed your random number generator.

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Gruß Jaraz

Super - hat geklappt

danke ;-)

Raudi